Past Papers of MDCAT ECAT Physics, Motion and Force Test 1

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Question 1: A ball is just allowed to fall from the window of a moving train, it will hit the ground following: (ETEA 2005)

A) Circular path

B) Hyperbolic

C) Straight line path

D) Parabolic path

Explanation: It has an initial horizontal velocity, which is same as that of train. It acquires a vertical component under the force of gravity.

Question 2: A particle moves along the straight line. The distance x describes in time, t is given by the equation x = t³ the acceleration a at t =1 (ETEA 2005)

A) a = 1

B) a = 2

C) a = 3

D) a = 4

Explanation: s = x = t³, v = s⁄t = x′⁄t = t², a = v/t = t² / t = t, At t=1, a = 1

Question 3: The vertical velocity of ball thrown upward ______ with time. (MCAT 2008)

A) Decreases linearly

B) Doubles

C) Remains constant

D) Decreases parabolically

Explanation: The vertical velocity of ball thrown upward decreases linearly with time.

Question 4: An ______ missile is called a ballistic missile. (MCAT 2008)

A) Un-powered and guided

B) Powered and guided

C) Un-guided and powered

D) Un-powered and un-guided

Explanation: An unpowered and unguided missile is called ballistic missile.

Question 5: A body is moving with an initial velocity of 2 kms⁻¹. After a time of 50 secs its velocity becomes 1.5 kms⁻¹. Its acceleration will be: (MCAT 2009)

A) 30 ms⁻²

B) 20 ms⁻²

C) 40 ms⁻²

D) 10 ms⁻²

Explanation: vᶠ = vᵢ + a × t, a = (vᶠ − vᵢ) ⁄ t, a = (1.5×10³ − 2×10³) ⁄ 50 = −0.5×10³ ⁄ 50 = −10 m/s²

Question 6: In elastic collision, when a massive body collides with light body at conditions m₁ >> m₂ and v₁ = 0 ms⁻¹, then the change in velocity will be written as: (MCAT 2009)

A) v₁' ≈ -v₁ ; v₂' ≈ v₁

B) v₁' ≈ v₁ ; v₂' ≈ 2v₁

C) v₁' = v₁ ; v₂' ≈ 0

D) v₁' ≈ -v₁ ; v₂' ≈ 0

Explanation: When a massive body collides with a light body then: v₁′ ≈ v₁, v₂′ ≈ 2v₁

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